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Chapter 1

83

Copyright © 2017 Pearson Education, Inc.

c. H

2

CO

The double-bonded carbon and the double-bonded oxygen in H

2

CO each uses

sp

2

orbitals; thus, the

bonds around the double-bonded carbon are all

120

°

.

Each carbon–hydrogen bond is formed by the

overlap of an

sp

2

orbital of carbon with the

s

orbital of hydrogen.

O

C

H H

sp –

2

s

overlap

the bond is formed by

sp

2

sp

2

overlap

the bond is formed by

p

p

overlap

sp –

2

s

overlap

all bond angles are 120

°

d.

N

2

The triple bond consists of one

s

bond and two

p

bonds. Each nitrogen has two

sp

orbitals; one is used to

form the

s

bond, and the other contains the lone pair. Each nitrogen has two

p

orbitals that are used to form

the two

p

bonds. A bond angle is the angle formed by three atoms. Therefore, there are no bond angles in

this two-atom containing compound.

N N the bond is formed by

sp

sp

overlap

each bond is formed by

p

p

overlap

s

p

e.

BF

3

Promotion gives boron three unpaired electrons, and hybridization gives it three

sp

2

orbitals.

1

s

2

s

2

p

x

promotion

hybridization

2

p

y

1

s

2

s

2

p

x

2

p

y

1

s

2

sp

2

2

sp

2

2

sp

2

Each

sp

2

orbital of boron overlaps an

sp

3

orbital of fluorine. The three

sp

2

orbitals orient themselves to

get as far away from each other as possible, resulting in bond angles of

120

°

.

F

B

F

F

bond angles

=

120

°

40.

Solved in the text.

41.

We know that the

s

bond is stronger than the

p

bond, because the

s

bond in ethane has a bond dissociation

energy of 90.2 kcal

>

mol, whereas the bond dissociation energy of the double bond

(

s

+

p

)

in ethene is

174.5 kcal

>

mol, which is less than twice as strong.

Because the

s

bond is stronger, we know that it has more effective orbital–orbital overlap.

42.

Because electrons in an

s

orbital are closer on average to the nucleus than those in a

p

orbital, the greater

the

s

character in the interacting orbitals, the stronger (and shorter) the bond. Therefore, the carbon–

carbon

s

bond formed by

sp

2

9

sp

2

overlap is stronger (and shorter) than the carbon–carbon bond formed by

sp

3

9

sp

3

overlap, because an

sp

2

orbital has 33.3%

s

character, whereas an

sp

3

orbital has 25%

s

character.