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452 Chapter 13

Copyright © 2017 Pearson Education, Inc.

69.

The broad absorption band at 3300 cm

-

1

indicates that the compound has an OH group. The absorption

bands at 2900 cm

-

1

indicate that the compound has hydrogens attached to an

sp

3

carbon. The compound,

therefore, is

benzyl alcohol

.

70.

In an acidic solution, the three benzene rings are isolated from one another, so phenolphthalein is colorless.

In a basic solution, loss of the proton from one of the OH groups causes the five-membered ring to open.

As a result, the number of conjugated double bonds increases, causing the solution to become colored.

C

C

O

O

O

C

O

O

OH

HO

O H

OH

71.

a.

The absorption bands at 1720 cm

-

1

and 2700 cm

-

1

(C—H of an aldehyde) indicate that the com-

pound is an aldehyde. The absence of an absorption band at 1600 cm

-

1

rules out the aldehyde with

the benzene ring. Therefore, it must be the other aldehyde.

H

O

b.

The absorption bands at 3350 cm

-

1

and 3200 cm

-

1

indicate that the compound is an amide

(nitrogen–hydrogen stretch). The absence of an absorption band at 3050 cm

-

1

indicates that the com-

pound does not have hydrogens bonded to

sp

2

carbons. Therefore, it is not the amide that has a benzene

ring. Thus, it must be the other amide.

NH

2

O

c.

The absence of absorption bands at 1600 cm

-

1

and 1500 cm

-

1

indicates that the compound does

not have a benzene ring. Therefore, it must be the ketone. This is confirmed by the absence of an

absorption band at 1380 cm

-

1

, indicating that the compound does not have a methyl group.

O