452 Chapter 13
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69.
The broad absorption band at 3300 cm
-
1
indicates that the compound has an OH group. The absorption
bands at 2900 cm
-
1
indicate that the compound has hydrogens attached to an
sp
3
carbon. The compound,
therefore, is
benzyl alcohol
.
70.
In an acidic solution, the three benzene rings are isolated from one another, so phenolphthalein is colorless.
In a basic solution, loss of the proton from one of the OH groups causes the five-membered ring to open.
As a result, the number of conjugated double bonds increases, causing the solution to become colored.
C
−
−
C
O
O
O
C
O
O
OH
HO
O H
OH
71.
a.
The absorption bands at 1720 cm
-
1
and 2700 cm
-
1
(C—H of an aldehyde) indicate that the com-
pound is an aldehyde. The absence of an absorption band at 1600 cm
-
1
rules out the aldehyde with
the benzene ring. Therefore, it must be the other aldehyde.
H
O
b.
The absorption bands at 3350 cm
-
1
and 3200 cm
-
1
indicate that the compound is an amide
(nitrogen–hydrogen stretch). The absence of an absorption band at 3050 cm
-
1
indicates that the com-
pound does not have hydrogens bonded to
sp
2
carbons. Therefore, it is not the amide that has a benzene
ring. Thus, it must be the other amide.
NH
2
O
c.
The absence of absorption bands at 1600 cm
-
1
and 1500 cm
-
1
indicates that the compound does
not have a benzene ring. Therefore, it must be the ketone. This is confirmed by the absence of an
absorption band at 1380 cm
-
1
, indicating that the compound does not have a methyl group.
O




