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Chapter 6 217

Copyright © 2017 Pearson Education, Inc.

b.

CH

3

CH

2

CH

2

CH

2

CH

3

C

H

CH

2

CH

2

CH

3

C

CH

2

CH

3

H

OH

HO

CH

2

CH

3

OH

CH

2

CH

2

CH

3

H

or

CH

2

CH

3

H

CH

2

CH

2

CH

3

HO

S

R

S

R

racemic

mixture

c.

CH

3

O

CH

3

This compound does not have any stereoisomers,

because it does not have any asymmetric centers.

d.

CH

3

CH

3

CCH

2

CH

3

CH

2

CH

3

Br

This compound does not have any stereoisomers,

because it does not have an asymmetric center.

38.

Solved in the text.

39.

Solved in the text.

40.

Solved in the text.

41.

a.

1.

trans

-3-heptene   

2.

cis

-3-heptene

b.

and

c.

The enantiomer of each of the structures shown is also formed, because the peroxyacid can

approach both the top and the bottom of the plane defined by the double bond.

O

C C

H CH

2

CH

3

H

CH

3

CH

2

CH

2

O

C C

CH

3

CH

2

CH

2

CH

2

CH

3

H

H

1.

2.

S

S S

R

42.

a.

OH

c.

CH

3

C

H

OH

CH

3

C

CH

2

CH

3

H

HO

+

or

CH

3

H

HO

CH

2

CH

3

CH

3

OH

H

CH

2

CH

3

CH

3

CH

2

S

R

R

S

b.

OH

+

HO CH

2

CH

3

CH

3

CH

2

R

S

S

R

d.

H

CH

2

CH

3

CH

2

CH

3

CH

3

CH

3

OH

CH

2

CH

2

CH

3

CH

3

CH

3

CH

3

H

HO

R

R

S

S