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200 Chapter 5

Copyright © 2017 Pearson Education, Inc.

47.

First draw the structures so you can see the number of alkyl groups bonded to the

sp

2

carbons:

CH

3

CH CCHCH

2

CH

3

CH

3

CH

3

3,4-dimethyl-2-hexene

CH

3

C CCH

2

CH

2

CH

3

2,3-dimethyl-2-hexene

CH

3

CH

3

CH

3

CH CHCHCHCH

3

4,5-dimethyl-2-hexene

CH

3

CH

3

a.

2,3-Dimethyl-2-hexene is the most stable of the three alkenes because it has the greatest number of

alkyl substituents bonded to the

sp

2

carbons.

b.

4,5-Dimethyl-2-hexene has the fewest alkyl substituents bonded to the

sp

2

carbons, making it the least

stable of the three alkenes. It, therefore, has the greatest heat of hydrogenation.

c.

Because it is the most stable, 2,3-dimethyl-2-hexene has the smallest heat of hydrogenation.

48.

H O H C

H

H

C H

H

Br

C

H

H

C

H

H

+

H

2

O

+

Br

+

49.

50.

G

°

=

-

RT

ln

K

eq

ln

K

eq

=

-

G

°

>

RT

ln

K

eq

=

-

G

°

>

0.59 kcal

>

mol

a.

ln

K

eq

=

-

2.72

>

0.59 kcal

>

mol

ln

K

eq

=

-

4.6

K

eq

=

3

B

4 > 3

A

4

=

0.01

b.

ln

K

eq

=

-

0.65

>

0.59 kcal

>

mol

ln

K

eq

=

-

1.10

K

eq

=

3

B

4 > 3

A

4

=

0.33

c.

ln

K

eq

=

2.72

>

0.59 kcal

>

mol

ln

K

eq

=

4.6

K

eq

=

3

B

4 > 3

A

4

=

100

d.

ln

K

eq

=

0.65

>

0.59 kcal

>

mol

ln

K

eq

=

1.10

K

eq

=

3

B

4 > 3

A

4

=

3.0

51.

a.

The C

¬

Cl bond is a stronger bond because Cl uses a 3

sp

3

orbital to overlap the 2

sp

3

orbital of carbon,

whereas Br uses a 4

sp

3

orbital. A 4

sp

3

has a greater volume than a 3

sp

3

and, therefore, has less electron

density in the region of orbital-orbital overlap, so it forms a weaker bond.

b.

The Br

¬

Br bond is a stronger bond because Br uses a 4

sp

3

orbital to overlap the 4

sp

3

orbital of the

other bromine, whereas I uses a 5

sp

3

orbital. A 5

sp

3

has a greater volume than a 4

sp

3

and, therefore,

has less electron density in the region of orbital–orbital overlap, so it forms a weaker bond.

46.

a.

a. the most stable because it has three alkyl groups attached to its

sp

2

carbons.

b.

d., e., and f. are the least stable because the two alkyl groups in d. and e. are on the same

sp

2

carbon,

and the two alkyl groups in f. are cis.