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Chapter 14 467

Copyright © 2017 Pearson Education, Inc.

29.

a.

CH

3

OCH

2

CH

2

OCH

3

b.

 There are three possibilities:

c.

HC

CH

O

O

CH

3

CCH

2

CH

2

CCH

3

O O

CH

3

OCH

2

C CCH

2

OCH

3

O

O CH

3

CH

3

30.

There is no coupling between

H

a

and

H

c

because they are separated by four

s

bonds. (We will see in

Section 14.17 that unless the sample is pure and dry, a proton bonded to an oxygen is not split and does not

split other protons.)

There is no coupling between

H

b

and

H

c

because they are separated by five

s

bonds.

31.

The two singlets in the

1

H

NMR spectrum that each integrate to 3 protons suggest two methyl groups, one

of which is adjacent to an oxygen. That the benzene ring protons (

6.7

-

7.1

ppm) consist of two doublets

(each integrating to two hydrogens) indicates a 1,4-disubstituted benzene ring. The IR spectrum also indi-

cates a benzene ring (1600 and

1500 cm

-

1

) with hydrogens bonded to

sp

2

carbons and no carbonyl group.

The absorption bands in the 1250–

1000 cm

-

1

region suggest that there are two C—O single bonds, one

with no double-bond character and one with some double-bond character.

CH

3

O

CH

3

32.

a.

J

bc

J

bc

J

ba

b.

J

ba

J

bc

J

bc

33.

a. A

 b. B

and

D

34.

Solved in the text.

35.

CH

3

CCH

3

Br

Br

a a

b a b

a b c

a d b

BrCH

2

CH

2

CH

2

Br

CH

3

CH

2

CHBr

Br

CH

3

CHCH

2

Br

Br

c

one signal

a singlet

two signals

a quintet (a) and

a triplet (b)

three signals

two triplets (a and c)

and a multiplet (b)

four signals

three doublets

(a, b, c) and a

multiplet (d)

36.

Solved in the text.

37.

The OH proton of a carboxylic acid is more deshielded than the OH proton of an alcohol as a result of

electron delocalization that decreases the electron density around the OH proton. In addition, the extent

of hydrogen bonding affects the chemical shift of a proton bonded to an oxygen. Carboxylic acids exist as

tightly hydrogen-bonded dimers (see page 693 in the text); this strongly deshields the OH proton.

R O

versus

H

C

O

R O H

C

O

R O H

+