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Special Topic I

129

Copyright © 2017 Pearson Education, Inc.

b.

x

x

y

y

mmol

mL

M

mmol of acetic acid

mmol

mL

M

50

1 00

50

50

1 50

33

=

=

=

=

.

.

.3

1 50

50

0 15

7 5

7 5

mL of

M aceticacid

mmol

mL

M

mmol of NaOH

m

.

.

.

.

x

x

=

=

mol

mL

M

mL of

M NaOH

y

y

=

=

1 50

5 0

1 50

.

.

.

33.3 mL of 1.50 M acetic acid

5.0 mL of 1.50 M NaOH

11.7 mL

50.0 mL

of H

2

O

c.

x

x

y

y

mmol

mL

M

mmol of sodium acetate

mmol

mL

M

50

1 00

50

50

1 50

=

=

=

=

.

.

33 3

1 50

50

0 85

42 5

.

.

.

.

mL of

M sodium acetate

mmol

mL

M

mmol o

x

x

=

=

f HCl

mmol

mL

M

mL of M HCl

42 5

1 5

28 3

1 5

.

.

.

.

y

y

=

=

We cannot make the required buffer with these solutions, because

33.3 mL

+

28.3 mL

7

50 mL.