Special Topic I
129
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b.
x
x
y
y
mmol
mL
M
mmol of acetic acid
mmol
mL
M
50
1 00
50
50
1 50
33
=
=
=
=
.
.
.3
1 50
50
0 15
7 5
7 5
mL of
M aceticacid
mmol
mL
M
mmol of NaOH
m
.
.
.
.
x
x
=
=
mol
mL
M
mL of
M NaOH
y
y
=
=
1 50
5 0
1 50
.
.
.
33.3 mL of 1.50 M acetic acid
5.0 mL of 1.50 M NaOH
11.7 mL
50.0 mL
of H
2
O
c.
x
x
y
y
mmol
mL
M
mmol of sodium acetate
mmol
mL
M
50
1 00
50
50
1 50
=
=
=
=
.
.
33 3
1 50
50
0 85
42 5
.
.
.
.
mL of
M sodium acetate
mmol
mL
M
mmol o
x
x
=
=
f HCl
mmol
mL
M
mL of M HCl
42 5
1 5
28 3
1 5
.
.
.
.
y
y
=
=
We cannot make the required buffer with these solutions, because
33.3 mL
+
28.3 mL
7
50 mL.




